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+--- Thread: Math Help (/showthread.php?tid=16996)
RE: Math Help - Shikari - 10-20-2010
Tch, it can't be 70 because the doubled number has to be less than 140 but cant be 140 itself. 70x2 IS 140
RE:??Math Help - Avogadro - 10-21-2010
Shikari Wrote:Tch, it can't be 70 because the doubled number has to be less than 140 but cant be 140 itself. 70x2 IS 140
No.
The double of the number (140) is zero less than 140. Zero is a valid number for this condition.
RE: Math Help - Kittie - 10-21-2010
This thread is giving me a headache @_@
*Ultimate math failer*
RE: Math Help - Merellis - 10-21-2010
Shikari, just make the doubled number must be more then 70 by the difference between the number and 140.
So make the number X to make it easier.
Find the value of X whose double exceeds 70 by as much as the value of X itself is less then 140.
2x - 70 = 140 - x
2x + x = 140 + 70
3x=210
x = 210/3
x = 70
2x - 70 = 140 - x
2(70) - 70 = 140 - 70
70 = 70
So x must equal 70, as doubled it is more then 70 by as much as 70 is less then 140.
RE:??Math Help - Ultima_Pi - 10-21-2010
Namine Wrote:The wording is certainly not best, but this would be how to interpret the question.
RE: Math Help - Shikari - 10-21-2010
loveapples Wrote:Find x so that 2x>70 as long as 2x-x>70-x. 2x must be equal to or less than 140.
Is that what its supposed to say then? O.o..
Well the yea...it would be 70 XD...
RE: Math Help - loveapples - 10-21-2010
How did this thread keep going? >_>
Thanks for you efforts everyone, but the correct answer indeed was 70.
RE: Math Help - Ngjoko - 10-21-2010
Because people have arguments over the right answer?
RE:??Math Help - Namine - 10-21-2010
loveapples Wrote:How did this thread keep going? >_>
Pride of my profession
RE: Math Help - Rankin - 10-21-2010
This is why I failed algebra II 3 years in a row and proceeded to math money in my 5th year. >_>....