More Math Help

[Zaratus]

1. ln 45 + ln (x-4) = ln (45* (x-4)), then just e^() and you have a linear equation.

2. log (x^2-49) - 1 = log (x^2-49) - log(10) = log ( (x^2-49)/10), then just 10^() and you have a quadratic equation. .. That you can solve with binomic formula like Nami there. Or do quadratic formula and get two solutions where one isn't defined for log(x+7).

Lemme think a sec about 3rd.

3. log'3'(13-x) - log'3'(x+3) = 1
(That's Log base 3 (13-x) minus Log base 3 (x+3) equals to 1)

log'3'(13-x) - log'3'(x+3) = log'3'( (13-x)/(x+3) then 3^() and linear equation again.