Downtime Puzzle, again

[katleoyumi]

I think C is the liar because:

A knows 6 other people so:
A = BCDEFG

G knows 1 person so:
G = A

B knows 5 people so:
B = ACDEF (because B cannot know G since G only knows one person aka A who knows everyone)

E and F only know 2 people and since B and A both know E and F, that means:
E = AB
F = AB

D only knows 3 people, and D cannot possibly know G, E, or F, therefore:
D = ABC

C CLAIMS to know 4 people, but cannot possibly know G, F, and E, therefore:
C = ABD_

C is missing one person so therefore C is the liar.